Base | Representation |
---|---|
bin | 100011100110001011010110… |
… | …0110111111110010100011111 |
3 | 1112001122001102221102200200202 |
4 | 1013030112230313332110133 |
5 | 312014444404131400111 |
6 | 3025532520300414115 |
7 | 122644321254126602 |
oct | 10714265467762437 |
9 | 1461561387380622 |
10 | 313110311200031 |
11 | 908483789a3534 |
12 | 2b14aa6184733b |
13 | 10593238ba9a57 |
14 | 57468970cc339 |
15 | 262eab75b0b3b |
hex | 11cc5acdfe51f |
313110311200031 has 2 divisors, whose sum is σ = 313110311200032. Its totient is φ = 313110311200030.
The previous prime is 313110311200013. The next prime is 313110311200039. The reversal of 313110311200031 is 130002113011313.
Together with previous prime (313110311200013) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 313110311200031 - 214 = 313110311183647 is a prime.
It is a super-2 number, since 2×3131103112000312 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 313110311199976 and 313110311200012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313110311200039) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156555155600015 + 156555155600016.
It is an arithmetic number, because the mean of its divisors is an integer number (156555155600016).
Almost surely, 2313110311200031 is an apocalyptic number.
313110311200031 is a deficient number, since it is larger than the sum of its proper divisors (1).
313110311200031 is an equidigital number, since it uses as much as digits as its factorization.
313110311200031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 313110311200031 its reverse (130002113011313), we get a palindrome (443112424211344).
The spelling of 313110311200031 in words is "three hundred thirteen trillion, one hundred ten billion, three hundred eleven million, two hundred thousand, thirty-one".
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