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313112021020 = 225101155005951
BaseRepresentation
bin1001000111001101110…
…11100100100000011100
31002221012022111201011021
410203212323210200130
520112223134133040
6355501445133524
731423131160021
oct4434673444034
91087168451137
10313112021020
11110876633807
12508246ba2a4
13236ac492826
141122470b548
15822888c24a
hex48e6ee481c

313112021020 has 24 divisors (see below), whose sum is σ = 664045498368. Its totient is φ = 124004760000.

The previous prime is 313112020957. The next prime is 313112021021. The reversal of 313112021020 is 20120211313.

It is a junction number, because it is equal to n+sod(n) for n = 313112020985 and 313112021003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (313112021021) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 77500956 + ... + 77504995.

It is an arithmetic number, because the mean of its divisors is an integer number (27668562432).

Almost surely, 2313112021020 is an apocalyptic number.

It is an amenable number.

313112021020 is an abundant number, since it is smaller than the sum of its proper divisors (350933477348).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

313112021020 is a wasteful number, since it uses less digits than its factorization.

313112021020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 155006061 (or 155006059 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 313112021020 its reverse (20120211313), we get a palindrome (333232232333).

The spelling of 313112021020 in words is "three hundred thirteen billion, one hundred twelve million, twenty-one thousand, twenty".

Divisors: 1 2 4 5 10 20 101 202 404 505 1010 2020 155005951 310011902 620023804 775029755 1550059510 3100119020 15655601051 31311202102 62622404204 78278005255 156556010510 313112021020