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31312230210133 is a prime number
BaseRepresentation
bin1110001111010011100100…
…10110111101101001010101
311002212102100011100020222221
413013221302112331221111
513101004421413211013
6150332350122422341
76411143153214115
oct707516226755125
9132772304306887
1031312230210133
119a82495711124
12361862a6619b1
1314619662a2002
147a373cd5b045
1539478279508d
hex1c7a725bda55

31312230210133 has 2 divisors, whose sum is σ = 31312230210134. Its totient is φ = 31312230210132.

The previous prime is 31312230210089. The next prime is 31312230210229. The reversal of 31312230210133 is 33101203221313.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31265341937764 + 46888272369 = 5591542^2 + 216537^2 .

It is a cyclic number.

It is not a de Polignac number, because 31312230210133 - 217 = 31312230079061 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31312230210098 and 31312230210107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31312230310133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15656115105066 + 15656115105067.

It is an arithmetic number, because the mean of its divisors is an integer number (15656115105067).

Almost surely, 231312230210133 is an apocalyptic number.

It is an amenable number.

31312230210133 is a deficient number, since it is larger than the sum of its proper divisors (1).

31312230210133 is an equidigital number, since it uses as much as digits as its factorization.

31312230210133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 31312230210133 its reverse (33101203221313), we get a palindrome (64413433431446).

The spelling of 31312230210133 in words is "thirty-one trillion, three hundred twelve billion, two hundred thirty million, two hundred ten thousand, one hundred thirty-three".