Base | Representation |
---|---|
bin | 101101100100001011111… |
… | …010111000000110011101 |
3 | 102002100020212211000210221 |
4 | 231210023322320012131 |
5 | 402300230133023201 |
6 | 10354245010201341 |
7 | 442136553363433 |
oct | 55441372700635 |
9 | 12070225730727 |
10 | 3131231142301 |
11 | aa7a47392289 |
12 | 426a2ab83251 |
13 | 1993737b0ab2 |
14 | ab7a3abad53 |
15 | 566b56e54a1 |
hex | 2d90beb819d |
3131231142301 has 2 divisors, whose sum is σ = 3131231142302. Its totient is φ = 3131231142300.
The previous prime is 3131231142289. The next prime is 3131231142337. The reversal of 3131231142301 is 1032411321313.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1566915615225 + 1564315527076 = 1251765^2 + 1250726^2 .
It is a cyclic number.
It is not a de Polignac number, because 3131231142301 - 221 = 3131229045149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3131231142371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1565615571150 + 1565615571151.
It is an arithmetic number, because the mean of its divisors is an integer number (1565615571151).
Almost surely, 23131231142301 is an apocalyptic number.
It is an amenable number.
3131231142301 is a deficient number, since it is larger than the sum of its proper divisors (1).
3131231142301 is an equidigital number, since it uses as much as digits as its factorization.
3131231142301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 3131231142301 its reverse (1032411321313), we get a palindrome (4163642463614).
The spelling of 3131231142301 in words is "three trillion, one hundred thirty-one billion, two hundred thirty-one million, one hundred forty-two thousand, three hundred one".
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