Base | Representation |
---|---|
bin | 1110001111010011111110… |
… | …01000000111010011100111 |
3 | 11002212102220002102022112202 |
4 | 13013221333020013103213 |
5 | 13101010341232440401 |
6 | 150332423254005115 |
7 | 6411151364040452 |
oct | 707517710072347 |
9 | 132772802368482 |
10 | 31312444421351 |
11 | 9a82595620195 |
12 | 361868a34679b |
13 | 146199b793902 |
14 | 7a375d59c499 |
15 | 3947964aa06b |
hex | 1c7a7f2074e7 |
31312444421351 has 2 divisors, whose sum is σ = 31312444421352. Its totient is φ = 31312444421350.
The previous prime is 31312444421311. The next prime is 31312444421359. The reversal of 31312444421351 is 15312444421313.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31312444421351 is a prime.
It is a super-2 number, since 2×313124444213512 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31312444421359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15656222210675 + 15656222210676.
It is an arithmetic number, because the mean of its divisors is an integer number (15656222210676).
Almost surely, 231312444421351 is an apocalyptic number.
31312444421351 is a deficient number, since it is larger than the sum of its proper divisors (1).
31312444421351 is an equidigital number, since it uses as much as digits as its factorization.
31312444421351 is an evil number, because the sum of its binary digits is even.
The product of its digits is 138240, while the sum is 38.
Subtracting from 31312444421351 its sum of digits (38), we obtain a palindrome (31312444421313).
Adding to 31312444421351 its reverse (15312444421313), we get a palindrome (46624888842664).
The spelling of 31312444421351 in words is "thirty-one trillion, three hundred twelve billion, four hundred forty-four million, four hundred twenty-one thousand, three hundred fifty-one".
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