Base | Representation |
---|---|
bin | 1110001111010101011101… |
… | …01011001101011001100011 |
3 | 11002212111221200111011012202 |
4 | 13013222232223031121203 |
5 | 13101014004442303444 |
6 | 150333034352043415 |
7 | 6411210221445431 |
oct | 707525653153143 |
9 | 132774850434182 |
10 | 31313242150499 |
11 | 9a8296494a981 |
12 | 361887153356b |
13 | 1461a97b2ccaa |
14 | 7a37d74d5d51 |
15 | 3947e153434e |
hex | 1c7aaeacd663 |
31313242150499 has 2 divisors, whose sum is σ = 31313242150500. Its totient is φ = 31313242150498.
The previous prime is 31313242150459. The next prime is 31313242150501. The reversal of 31313242150499 is 99405124231313.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31313242150499 is a prime.
Together with 31313242150501, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (31313242150459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15656621075249 + 15656621075250.
It is an arithmetic number, because the mean of its divisors is an integer number (15656621075250).
Almost surely, 231313242150499 is an apocalyptic number.
31313242150499 is a deficient number, since it is larger than the sum of its proper divisors (1).
31313242150499 is an equidigital number, since it uses as much as digits as its factorization.
31313242150499 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 699840, while the sum is 47.
The spelling of 31313242150499 in words is "thirty-one trillion, three hundred thirteen billion, two hundred forty-two million, one hundred fifty thousand, four hundred ninety-nine".
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