Base | Representation |
---|---|
bin | 1001000111100100110… |
… | …01110111101010010101 |
3 | 1002221200201201022202021 |
4 | 10203302121313222111 |
5 | 20113121423410143 |
6 | 355532523013141 |
7 | 31430656264441 |
oct | 4436231675225 |
9 | 1087621638667 |
10 | 313304513173 |
11 | 110965258a33 |
12 | 5087906a1b1 |
13 | 2371031b702 |
14 | 112420d7821 |
15 | 823a711ced |
hex | 48f2677a95 |
313304513173 has 2 divisors, whose sum is σ = 313304513174. Its totient is φ = 313304513172.
The previous prime is 313304513149. The next prime is 313304513219. The reversal of 313304513173 is 371315403313.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 279484567569 + 33819945604 = 528663^2 + 183902^2 .
It is an emirp because it is prime and its reverse (371315403313) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-313304513173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313304519173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156652256586 + 156652256587.
It is an arithmetic number, because the mean of its divisors is an integer number (156652256587).
Almost surely, 2313304513173 is an apocalyptic number.
It is an amenable number.
313304513173 is a deficient number, since it is larger than the sum of its proper divisors (1).
313304513173 is an equidigital number, since it uses as much as digits as its factorization.
313304513173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34020, while the sum is 34.
Adding to 313304513173 its reverse (371315403313), we get a palindrome (684619916486).
The spelling of 313304513173 in words is "three hundred thirteen billion, three hundred four million, five hundred thirteen thousand, one hundred seventy-three".
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