Base | Representation |
---|---|
bin | 100011100111101101111111… |
… | …0111000010011000010101011 |
3 | 1112002101022012200110201022121 |
4 | 1013033123332320103002223 |
5 | 312031432220421222443 |
6 | 3030214112035532111 |
7 | 122665530503546341 |
oct | 10717337670230253 |
9 | 1462338180421277 |
10 | 313322140414123 |
11 | 9091a19aa77325 |
12 | 2b183b1aa5a037 |
13 | 105aa1c6b64799 |
14 | 5752c30251991 |
15 | 26353642bc4ed |
hex | 11cf6fee130ab |
313322140414123 has 2 divisors, whose sum is σ = 313322140414124. Its totient is φ = 313322140414122.
The previous prime is 313322140414043. The next prime is 313322140414223. The reversal of 313322140414123 is 321414041223313.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 313322140414123 - 213 = 313322140405931 is a prime.
It is not a weakly prime, because it can be changed into another prime (313322140414223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156661070207061 + 156661070207062.
It is an arithmetic number, because the mean of its divisors is an integer number (156661070207062).
Almost surely, 2313322140414123 is an apocalyptic number.
313322140414123 is a deficient number, since it is larger than the sum of its proper divisors (1).
313322140414123 is an equidigital number, since it uses as much as digits as its factorization.
313322140414123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 313322140414123 its reverse (321414041223313), we get a palindrome (634736181637436).
The spelling of 313322140414123 in words is "three hundred thirteen trillion, three hundred twenty-two billion, one hundred forty million, four hundred fourteen thousand, one hundred twenty-three".
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