Base | Representation |
---|---|
bin | 1110001111111001011000… |
… | …10101000111000000010100 |
3 | 11002221100201220021022222211 |
4 | 13013330230111013000110 |
5 | 13101323010204434130 |
6 | 150345544325003204 |
7 | 6412462210002325 |
oct | 707745425070024 |
9 | 132840656238884 |
10 | 31332530155540 |
11 | 9a90062487609 |
12 | 3620554b53504 |
13 | 146384cb58923 |
14 | 7a470700044c |
15 | 39506ea0da2a |
hex | 1c7f2c547014 |
31332530155540 has 24 divisors (see below), whose sum is σ = 65813821002720. Its totient is φ = 12530058219168.
The previous prime is 31332530155523. The next prime is 31332530155631. The reversal of 31332530155540 is 4555103523313.
It is a junction number, because it is equal to n+sod(n) for n = 31332530155493 and 31332530155502.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 184528210 + ... + 184697929.
It is an arithmetic number, because the mean of its divisors is an integer number (2742242541780).
Almost surely, 231332530155540 is an apocalyptic number.
It is an amenable number.
31332530155540 is an abundant number, since it is smaller than the sum of its proper divisors (34481290847180).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31332530155540 is a wasteful number, since it uses less digits than its factorization.
31332530155540 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 369230391 (or 369230389 counting only the distinct ones).
The product of its (nonzero) digits is 405000, while the sum is 40.
Adding to 31332530155540 its reverse (4555103523313), we get a palindrome (35887633678853).
The spelling of 31332530155540 in words is "thirty-one trillion, three hundred thirty-two billion, five hundred thirty million, one hundred fifty-five thousand, five hundred forty".
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