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313401201541 is a prime number
BaseRepresentation
bin1001000111110000010…
…10101101001110000101
31002221221110122121020221
410203320022231032011
520113321201422131
6355550255224341
731433242154641
oct4437012551605
91087843577227
10313401201541
11110a0489837a
12508a55180b1
1323727372a6c
1411250ca5c21
158243e60411
hex48f82ad385

313401201541 has 2 divisors, whose sum is σ = 313401201542. Its totient is φ = 313401201540.

The previous prime is 313401201473. The next prime is 313401201551. The reversal of 313401201541 is 145102104313.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 298939936516 + 14461265025 = 546754^2 + 120255^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-313401201541 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (313401201551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156700600770 + 156700600771.

It is an arithmetic number, because the mean of its divisors is an integer number (156700600771).

Almost surely, 2313401201541 is an apocalyptic number.

It is an amenable number.

313401201541 is a deficient number, since it is larger than the sum of its proper divisors (1).

313401201541 is an equidigital number, since it uses as much as digits as its factorization.

313401201541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 313401201541 its reverse (145102104313), we get a palindrome (458503305854).

The spelling of 313401201541 in words is "three hundred thirteen billion, four hundred one million, two hundred one thousand, five hundred forty-one".