Base | Representation |
---|---|
bin | 101101100110110110111… |
… | …010110111000110010101 |
3 | 102002121122211011020112021 |
4 | 231212312322313012111 |
5 | 402322114102322013 |
6 | 10355441412453141 |
7 | 442300630544044 |
oct | 55466672670625 |
9 | 12077584136467 |
10 | 3134100042133 |
11 | aa918984a185 |
12 | 4274ab91a1b1 |
13 | 19970cc82b68 |
14 | ab996b1855b |
15 | 567d24dea8d |
hex | 2d9b6eb7195 |
3134100042133 has 2 divisors, whose sum is σ = 3134100042134. Its totient is φ = 3134100042132.
The previous prime is 3134100042089. The next prime is 3134100042251. The reversal of 3134100042133 is 3312400014313.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3051111108049 + 82988934084 = 1746743^2 + 288078^2 .
It is a cyclic number.
It is not a de Polignac number, because 3134100042133 - 29 = 3134100041621 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3134100042098 and 3134100042107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3134100042433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1567050021066 + 1567050021067.
It is an arithmetic number, because the mean of its divisors is an integer number (1567050021067).
Almost surely, 23134100042133 is an apocalyptic number.
It is an amenable number.
3134100042133 is a deficient number, since it is larger than the sum of its proper divisors (1).
3134100042133 is an equidigital number, since it uses as much as digits as its factorization.
3134100042133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 3134100042133 its reverse (3312400014313), we get a palindrome (6446500056446).
The spelling of 3134100042133 in words is "three trillion, one hundred thirty-four billion, one hundred million, forty-two thousand, one hundred thirty-three".
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