Base | Representation |
---|---|
bin | 101101100110111010101… |
… | …011100100110110000111 |
3 | 102002121211012220011010002 |
4 | 231212322223210312013 |
5 | 402322231231102241 |
6 | 10355451545151515 |
7 | 442302325110521 |
oct | 55467253446607 |
9 | 12077735804102 |
10 | 3134163144071 |
11 | aa9211429643 |
12 | 427508a8b59b |
13 | 19972007799b |
14 | ab9a1262a11 |
15 | 567d7d0689b |
hex | 2d9baae4d87 |
3134163144071 has 2 divisors, whose sum is σ = 3134163144072. Its totient is φ = 3134163144070.
The previous prime is 3134163143941. The next prime is 3134163144127. The reversal of 3134163144071 is 1704413614313.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3134163144071 - 210 = 3134163143047 is a prime.
It is a super-2 number, since 2×31341631440712 (a number of 26 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3134103144071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1567081572035 + 1567081572036.
It is an arithmetic number, because the mean of its divisors is an integer number (1567081572036).
Almost surely, 23134163144071 is an apocalyptic number.
3134163144071 is a deficient number, since it is larger than the sum of its proper divisors (1).
3134163144071 is an equidigital number, since it uses as much as digits as its factorization.
3134163144071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72576, while the sum is 38.
Adding to 3134163144071 its reverse (1704413614313), we get a palindrome (4838576758384).
The spelling of 3134163144071 in words is "three trillion, one hundred thirty-four billion, one hundred sixty-three million, one hundred forty-four thousand, seventy-one".
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