Base | Representation |
---|---|
bin | 100011101000100101011011… |
… | …1101001011111010011110111 |
3 | 1112002210200112110102121200202 |
4 | 1013101022313221133103313 |
5 | 312040410041313343132 |
6 | 3030344522415031115 |
7 | 123010244146200245 |
oct | 10721126751372367 |
9 | 1462720473377622 |
10 | 313441204434167 |
11 | 90965739564897 |
12 | 2b1a300920b49b |
13 | 105b84c0168654 |
14 | 57588c7153795 |
15 | 26384d1eda762 |
hex | 11d12b7a5f4f7 |
313441204434167 has 2 divisors, whose sum is σ = 313441204434168. Its totient is φ = 313441204434166.
The previous prime is 313441204434131. The next prime is 313441204434179. The reversal of 313441204434167 is 761434402144313.
It is a strong prime.
It is an emirp because it is prime and its reverse (761434402144313) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 313441204434167 - 234 = 313424024564983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313441204434667) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156720602217083 + 156720602217084.
It is an arithmetic number, because the mean of its divisors is an integer number (156720602217084).
Almost surely, 2313441204434167 is an apocalyptic number.
313441204434167 is a deficient number, since it is larger than the sum of its proper divisors (1).
313441204434167 is an equidigital number, since it uses as much as digits as its factorization.
313441204434167 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2322432, while the sum is 47.
The spelling of 313441204434167 in words is "three hundred thirteen trillion, four hundred forty-one billion, two hundred four million, four hundred thirty-four thousand, one hundred sixty-seven".
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