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31344410248391 is a prime number
BaseRepresentation
bin1110010000001111100000…
…11100000100010011000111
311002222111101211202120122202
413020013300130010103013
513102021323010422031
6150355231232345115
76413362464062462
oct710076034042307
9132874354676582
1031344410248391
119a950a9490169
12362290b6a519b
1314649c41c9876
147a5112b282d9
153955179962cb
hex1c81f07044c7

31344410248391 has 2 divisors, whose sum is σ = 31344410248392. Its totient is φ = 31344410248390.

The previous prime is 31344410248369. The next prime is 31344410248423. The reversal of 31344410248391 is 19384201444313.

It is a weak prime.

It is an emirp because it is prime and its reverse (19384201444313) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31344410248391 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31344410248691) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15672205124195 + 15672205124196.

It is an arithmetic number, because the mean of its divisors is an integer number (15672205124196).

Almost surely, 231344410248391 is an apocalyptic number.

31344410248391 is a deficient number, since it is larger than the sum of its proper divisors (1).

31344410248391 is an equidigital number, since it uses as much as digits as its factorization.

31344410248391 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 995328, while the sum is 47.

The spelling of 31344410248391 in words is "thirty-one trillion, three hundred forty-four billion, four hundred ten million, two hundred forty-eight thousand, three hundred ninety-one".