Base | Representation |
---|---|
bin | 101101101000000110111… |
… | …111000110101001110100 |
3 | 102002202010102210102101201 |
4 | 231220012333012221310 |
5 | 402332341443103300 |
6 | 10400223000102244 |
7 | 442346131403131 |
oct | 55500677065164 |
9 | 12082112712351 |
10 | 3135443331700 |
11 | aa9809024549 |
12 | 427805764984 |
13 | 199895366a64 |
14 | aba832a7588 |
15 | 568603d166a |
hex | 2da06fc6a74 |
3135443331700 has 36 divisors (see below), whose sum is σ = 6804028468300. Its totient is φ = 1254155869440.
The previous prime is 3135443331667. The next prime is 3135443331707. The reversal of 3135443331700 is 71333445313.
It can be written as a sum of positive squares in 6 ways, for example, as 188734638096 + 2946708693604 = 434436^2 + 1716598^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 3135443331700.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3135443331707) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6438376 + ... + 6908224.
Almost surely, 23135443331700 is an apocalyptic number.
It is an amenable number.
3135443331700 is an abundant number, since it is smaller than the sum of its proper divisors (3668585136600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3135443331700 is a wasteful number, since it uses less digits than its factorization.
3135443331700 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 536596 (or 536589 counting only the distinct ones).
The product of its (nonzero) digits is 136080, while the sum is 37.
The spelling of 3135443331700 in words is "three trillion, one hundred thirty-five billion, four hundred forty-three million, three hundred thirty-one thousand, seven hundred".
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