314001431 has 2 divisors, whose sum is σ = 314001432. Its totient is φ = 314001430.

The previous prime is 314001421. The next prime is 314001433. The reversal of 314001431 is 134100413.

It is a strong prime.

It is an emirp because it is prime and its reverse (134100413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 314001431 - 2¹⁴ = 313985047 is a prime.

It is a super-2 number, since 2×314001431² = 197193797340095522, which contains 22 as substring.

Together with 314001433, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (314001433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157000715 + 157000716.

It is an arithmetic number, because the mean of its divisors is an integer number (157000716).

Almost surely, 2^314001431 is an apocalyptic number.

314001431 is a deficient number, since it is larger than the sum of its proper divisors (1).

314001431 is an equidigital number, since it uses as much as digits as its factorization.

314001431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 314001431 is about 17720.0855246243. The cubic root of 314001431 is about 679.6894711047.

Adding to 314001431 its reverse (134100413), we get a palindrome (448101844).

It can be divided in two parts, 314001 and 431, that added together give a cube (314432 = 68³).

The spelling of 314001431 in words is "three hundred fourteen million, one thousand, four hundred thirty-one".