Base | Representation |
---|---|
bin | 1011101100101001… |
… | …0100011000111111 |
3 | 22002211112210001221 |
4 | 2323022110120333 |
5 | 22412322404401 |
6 | 1235330014211 |
7 | 140545636153 |
oct | 27312243077 |
9 | 8084483057 |
10 | 3140044351 |
11 | 1371522884 |
12 | 737717367 |
13 | 3b0708b12 |
14 | 21b05d063 |
15 | 135a087a1 |
hex | bb29463f |
3140044351 has 2 divisors, whose sum is σ = 3140044352. Its totient is φ = 3140044350.
The previous prime is 3140044337. The next prime is 3140044373. The reversal of 3140044351 is 1534400413.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3140044351 - 25 = 3140044319 is a prime.
It is a super-2 number, since 2×31400443512 = 19719757052494022402, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3140044151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1570022175 + 1570022176.
It is an arithmetic number, because the mean of its divisors is an integer number (1570022176).
Almost surely, 23140044351 is an apocalyptic number.
3140044351 is a deficient number, since it is larger than the sum of its proper divisors (1).
3140044351 is an equidigital number, since it uses as much as digits as its factorization.
3140044351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 25.
The square root of 3140044351 is about 56036.0986418576. The cubic root of 3140044351 is about 1464.3512448588.
Adding to 3140044351 its reverse (1534400413), we get a palindrome (4674444764).
The spelling of 3140044351 in words is "three billion, one hundred forty million, forty-four thousand, three hundred fifty-one".
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