Search a number
-
+
31411004331310 = 2529108313808039
BaseRepresentation
bin1110010010001011100011…
…10000010101010100101110
311010012212021220021111122021
413021011301300111110232
513104114214102100220
6150450003254540354
76421240653331642
oct711056160252456
9133185256244567
1031411004331310
11a01037207532a
1236337b59676ba
13146b077b29066
147a842d272c22
153971140814aa
hex1c9171c1552e

31411004331310 has 16 divisors (see below), whose sum is σ = 58489456341600. Its totient is φ = 12131146500256.

The previous prime is 31411004331283. The next prime is 31411004331319. The reversal of 31411004331310 is 1313340011413.

It is a super-2 number, since 2×314110043313102 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31411004331319) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 54156903730 + ... + 54156904309.

It is an arithmetic number, because the mean of its divisors is an integer number (3655591021350).

Almost surely, 231411004331310 is an apocalyptic number.

31411004331310 is a deficient number, since it is larger than the sum of its proper divisors (27078452010290).

31411004331310 is a wasteful number, since it uses less digits than its factorization.

31411004331310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 108313808075.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 31411004331310 its reverse (1313340011413), we get a palindrome (32724344342723).

The spelling of 31411004331310 in words is "thirty-one trillion, four hundred eleven billion, four million, three hundred thirty-one thousand, three hundred ten".

Divisors: 1 2 5 10 29 58 145 290 108313808039 216627616078 541569040195 1083138080390 3141100433131 6282200866262 15705502165655 31411004331310