Base | Representation |
---|---|
bin | 1110010010001011100011… |
… | …10000010101010100101110 |
3 | 11010012212021220021111122021 |
4 | 13021011301300111110232 |
5 | 13104114214102100220 |
6 | 150450003254540354 |
7 | 6421240653331642 |
oct | 711056160252456 |
9 | 133185256244567 |
10 | 31411004331310 |
11 | a01037207532a |
12 | 36337b59676ba |
13 | 146b077b29066 |
14 | 7a842d272c22 |
15 | 3971140814aa |
hex | 1c9171c1552e |
31411004331310 has 16 divisors (see below), whose sum is σ = 58489456341600. Its totient is φ = 12131146500256.
The previous prime is 31411004331283. The next prime is 31411004331319. The reversal of 31411004331310 is 1313340011413.
It is a super-2 number, since 2×314110043313102 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31411004331319) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 54156903730 + ... + 54156904309.
It is an arithmetic number, because the mean of its divisors is an integer number (3655591021350).
Almost surely, 231411004331310 is an apocalyptic number.
31411004331310 is a deficient number, since it is larger than the sum of its proper divisors (27078452010290).
31411004331310 is a wasteful number, since it uses less digits than its factorization.
31411004331310 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 108313808075.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 31411004331310 its reverse (1313340011413), we get a palindrome (32724344342723).
The spelling of 31411004331310 in words is "thirty-one trillion, four hundred eleven billion, four million, three hundred thirty-one thousand, three hundred ten".
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