Base | Representation |
---|---|
bin | 101101101101011001011… |
… | …111000110110110101111 |
3 | 102010021210020000000011201 |
4 | 231231121133012312233 |
5 | 402431004314421033 |
6 | 10403002310430331 |
7 | 442636641015241 |
oct | 55553137066657 |
9 | 12107706000151 |
10 | 3141122420143 |
11 | 1001162798774 |
12 | 42892b6623a7 |
13 | 19a28bac2716 |
14 | ac06161c091 |
15 | 56a93c7947d |
hex | 2db597c6daf |
3141122420143 has 2 divisors, whose sum is σ = 3141122420144. Its totient is φ = 3141122420142.
The previous prime is 3141122420131. The next prime is 3141122420167. The reversal of 3141122420143 is 3410242211413.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3141122420143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3141122420113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1570561210071 + 1570561210072.
It is an arithmetic number, because the mean of its divisors is an integer number (1570561210072).
Almost surely, 23141122420143 is an apocalyptic number.
3141122420143 is a deficient number, since it is larger than the sum of its proper divisors (1).
3141122420143 is an equidigital number, since it uses as much as digits as its factorization.
3141122420143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 3141122420143 its reverse (3410242211413), we get a palindrome (6551364631556).
The spelling of 3141122420143 in words is "three trillion, one hundred forty-one billion, one hundred twenty-two million, four hundred twenty thousand, one hundred forty-three".
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