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3141431141 is a prime number
BaseRepresentation
bin1011101100111110…
…0110111101100101
322002221011020101112
42323033212331211
522413201244031
61235415434405
7140563503242
oct27317467545
98087136345
103141431141
11137228a792
12738085a05
133b0aa30c4
1421b3005c9
15135bce62b
hexbb3e6f65

3141431141 has 2 divisors, whose sum is σ = 3141431142. Its totient is φ = 3141431140.

The previous prime is 3141431123. The next prime is 3141431143. The reversal of 3141431141 is 1411341413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3034908100 + 106523041 = 55090^2 + 10321^2 .

It is a cyclic number.

It is not a de Polignac number, because 3141431141 - 218 = 3141168997 is a prime.

It is a super-2 number, since 2×31414311412 = 19737179227289123762, which contains 22 as substring.

Together with 3141431143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3141431143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1570715570 + 1570715571.

It is an arithmetic number, because the mean of its divisors is an integer number (1570715571).

Almost surely, 23141431141 is an apocalyptic number.

It is an amenable number.

3141431141 is a deficient number, since it is larger than the sum of its proper divisors (1).

3141431141 is an equidigital number, since it uses as much as digits as its factorization.

3141431141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 576, while the sum is 23.

The square root of 3141431141 is about 56048.4713529281. The cubic root of 3141431141 is about 1464.5667883938.

Adding to 3141431141 its reverse (1411341413), we get a palindrome (4552772554).

The spelling of 3141431141 in words is "three billion, one hundred forty-one million, four hundred thirty-one thousand, one hundred forty-one".