Base | Representation |
---|---|
bin | 100011101101101100011011… |
… | …0011011101110000001110111 |
3 | 1112012021211001110100100012222 |
4 | 1013123120312123232001313 |
5 | 312133411201231400434 |
6 | 3032043254003032555 |
7 | 123112053403212614 |
oct | 10733306633560167 |
9 | 1465254043310188 |
10 | 314143411200119 |
11 | 91106521a143a6 |
12 | 2b29712096b75b |
13 | 1063979a865757 |
14 | 578089d57750b |
15 | 264b8ceb9972e |
hex | 11db6366ee077 |
314143411200119 has 2 divisors, whose sum is σ = 314143411200120. Its totient is φ = 314143411200118.
The previous prime is 314143411200023. The next prime is 314143411200121. The reversal of 314143411200119 is 911002114341413.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 314143411200119 - 236 = 314074691723383 is a prime.
It is a super-2 number, since 2×3141434112001192 (a number of 30 digits) contains 22 as substring.
Together with 314143411200121, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (314143411280119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157071705600059 + 157071705600060.
It is an arithmetic number, because the mean of its divisors is an integer number (157071705600060).
Almost surely, 2314143411200119 is an apocalyptic number.
314143411200119 is a deficient number, since it is larger than the sum of its proper divisors (1).
314143411200119 is an equidigital number, since it uses as much as digits as its factorization.
314143411200119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 35.
The spelling of 314143411200119 in words is "three hundred fourteen trillion, one hundred forty-three billion, four hundred eleven million, two hundred thousand, one hundred nineteen".
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