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3142224113141 is a prime number
BaseRepresentation
bin101101101110011011001…
…001101110110111110101
3102010101122000000210212002
4231232123021232313311
5402440233333110031
610403303503505045
7443006146162211
oct55563311566765
912111560023762
103142224113141
111001678659a53
12428b985b8185
1319a406116b79
14ac127a7b941
1556b0a846ccb
hex2db9b26edf5

3142224113141 has 2 divisors, whose sum is σ = 3142224113142. Its totient is φ = 3142224113140.

The previous prime is 3142224113117. The next prime is 3142224113143. The reversal of 3142224113141 is 1413114222413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1836895013041 + 1305329100100 = 1355321^2 + 1142510^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3142224113141 is a prime.

Together with 3142224113143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3142224113143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1571112056570 + 1571112056571.

It is an arithmetic number, because the mean of its divisors is an integer number (1571112056571).

Almost surely, 23142224113141 is an apocalyptic number.

It is an amenable number.

3142224113141 is a deficient number, since it is larger than the sum of its proper divisors (1).

3142224113141 is an equidigital number, since it uses as much as digits as its factorization.

3142224113141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4608, while the sum is 29.

Adding to 3142224113141 its reverse (1413114222413), we get a palindrome (4555338335554).

The spelling of 3142224113141 in words is "three trillion, one hundred forty-two billion, two hundred twenty-four million, one hundred thirteen thousand, one hundred forty-one".