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314224212437 is a prime number
BaseRepresentation
bin1001001001010010011…
…10001111100111010101
31010001001211021212221222
410210221032033213111
520122012344244222
6400204055220125
731462524510422
oct4445116174725
91101054255858
10314224212437
11111297415673
1250a95077645
1323828a21665
14112cc300d49
158291330542
hex492938f9d5

314224212437 has 2 divisors, whose sum is σ = 314224212438. Its totient is φ = 314224212436.

The previous prime is 314224212409. The next prime is 314224212593. The reversal of 314224212437 is 734212422413.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 283203844561 + 31020367876 = 532169^2 + 176126^2 .

It is an emirp because it is prime and its reverse (734212422413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 314224212437 - 220 = 314223163861 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 314224212397 and 314224212406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (314224232437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157112106218 + 157112106219.

It is an arithmetic number, because the mean of its divisors is an integer number (157112106219).

Almost surely, 2314224212437 is an apocalyptic number.

It is an amenable number.

314224212437 is a deficient number, since it is larger than the sum of its proper divisors (1).

314224212437 is an equidigital number, since it uses as much as digits as its factorization.

314224212437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 64512, while the sum is 35.

The spelling of 314224212437 in words is "three hundred fourteen billion, two hundred twenty-four million, two hundred twelve thousand, four hundred thirty-seven".