Base | Representation |
---|---|
bin | 1110010010100100100101… |
… | …01001101111101000000010 |
3 | 11010021010222100000211020202 |
4 | 13021102102221233220002 |
5 | 13104324223413412200 |
6 | 150500104452405202 |
7 | 6422224642414160 |
oct | 711222251575002 |
9 | 133233870024222 |
10 | 31424441154050 |
11 | a01603788610a |
12 | 3636325916802 |
13 | 146c409862949 |
14 | 7a8d45a2a230 |
15 | 39764da1c1d5 |
hex | 1c9492a6fa02 |
31424441154050 has 48 divisors (see below), whose sum is σ = 66817582722432. Its totient is φ = 10771158748800.
The previous prime is 31424441154047. The next prime is 31424441154077. The reversal of 31424441154050 is 5045114442413.
It is a junction number, because it is equal to n+sod(n) for n = 31424441153995 and 31424441154013.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 10943987 + ... + 13513686.
It is an arithmetic number, because the mean of its divisors is an integer number (1392032973384).
Almost surely, 231424441154050 is an apocalyptic number.
31424441154050 is an abundant number, since it is smaller than the sum of its proper divisors (35393141568382).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31424441154050 is a wasteful number, since it uses less digits than its factorization.
31424441154050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24461363 (or 24461358 counting only the distinct ones).
The product of its (nonzero) digits is 153600, while the sum is 38.
Adding to 31424441154050 its reverse (5045114442413), we get a palindrome (36469555596463).
The spelling of 31424441154050 in words is "thirty-one trillion, four hundred twenty-four billion, four hundred forty-one million, one hundred fifty-four thousand, fifty".
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