Base | Representation |
---|---|
bin | 101101110000011111100… |
… | …110010100111001111111 |
3 | 102010121100212021120222212 |
4 | 231300133212110321333 |
5 | 403004311211421341 |
6 | 10404312202531035 |
7 | 443115210465641 |
oct | 55603746247177 |
9 | 12117325246885 |
10 | 3144446201471 |
11 | 10026089a5893 |
12 | 4294b8806a7b |
13 | 19a69b5b0333 |
14 | ac298c28891 |
15 | 56bda9785eb |
hex | 2dc1f994e7f |
3144446201471 has 2 divisors, whose sum is σ = 3144446201472. Its totient is φ = 3144446201470.
The previous prime is 3144446201371. The next prime is 3144446201473. The reversal of 3144446201471 is 1741026444413.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3144446201471 is a prime.
It is a super-3 number, since 3×31444462014713 (a number of 38 digits) contains 333 as substring.
Together with 3144446201473, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3144446201473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1572223100735 + 1572223100736.
It is an arithmetic number, because the mean of its divisors is an integer number (1572223100736).
Almost surely, 23144446201471 is an apocalyptic number.
3144446201471 is a deficient number, since it is larger than the sum of its proper divisors (1).
3144446201471 is an equidigital number, since it uses as much as digits as its factorization.
3144446201471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 258048, while the sum is 41.
The spelling of 3144446201471 in words is "three trillion, one hundred forty-four billion, four hundred forty-six million, two hundred one thousand, four hundred seventy-one".
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