3145114115413 has 2 divisors, whose sum is σ = 3145114115414. Its totient is φ = 3145114115412.

The previous prime is 3145114115393. The next prime is 3145114115431.

3145114115413 is nontrivially palindromic in base 10.

Together with next prime (3145114115431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1811936750724 + 1333177364689 = 1346082^2 + 1154633^2 .

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 3145114115413 - 2²¹ = 3145112018261 is a prime.

It is a super-3 number, since 3×3145114115413³ (a number of 38 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3145111115413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1572557057706 + 1572557057707.

It is an arithmetic number, because the mean of its divisors is an integer number (1572557057707).

Almost surely, 2^{3145114115413} is an apocalyptic number.

It is an amenable number.

3145114115413 is a deficient number, since it is larger than the sum of its proper divisors (1).

3145114115413 is an equidigital number, since it uses as much as digits as its factorization.

3145114115413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 14400, while the sum is 34.

The spelling of 3145114115413 in words is "three trillion, one hundred forty-five billion, one hundred fourteen million, one hundred fifteen thousand, four hundred thirteen".