31451144114050 has 12 divisors (see below), whose sum is σ = 58499128052226. Its totient is φ = 12580457645600.

The previous prime is 31451144113967. The next prime is 31451144114053. The reversal of 31451144114050 is 5041144115413.

It can be written as a sum of positive squares in 3 ways, for example, as 27196235430001 + 4254908684049 = 5215001^2 + 2062743^2 .

It is a super-3 number, since 3×31451144114050³ (a number of 41 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31451144113997 and 31451144114015.

It is not an unprimeable number, because it can be changed into a prime (31451144114053) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 314511441091 + ... + 314511441190.

Almost surely, 2^{31451144114050} is an apocalyptic number.

31451144114050 is a deficient number, since it is larger than the sum of its proper divisors (27047983938176).

31451144114050 is a wasteful number, since it uses less digits than its factorization.

31451144114050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 629022882293 (or 629022882288 counting only the distinct ones).

The product of its (nonzero) digits is 19200, while the sum is 34.

Adding to 31451144114050 its reverse (5041144115413), we get a palindrome (36492288229463).

The spelling of 31451144114050 in words is "thirty-one trillion, four hundred fifty-one billion, one hundred forty-four million, one hundred fourteen thousand, fifty".