Base | Representation |
---|---|
bin | 11101010011110100… |
… | …110011110000101100 |
3 | 10000020021110201102200 |
4 | 131103310303300230 |
5 | 1003423101423000 |
6 | 22242503221500 |
7 | 2162612064435 |
oct | 352364636054 |
9 | 100207421380 |
10 | 31471123500 |
11 | 1238a6a0983 |
12 | 6123747890 |
13 | 2c770b688b |
14 | 174799248c |
15 | c42d6c500 |
hex | 753d33c2c |
31471123500 has 72 divisors (see below), whose sum is σ = 99280918464. Its totient is φ = 8392298400.
The previous prime is 31471123483. The next prime is 31471123501. The reversal of 31471123500 is 532117413.
31471123500 is a `hidden beast` number, since 3 + 1 + 47 + 112 + 3 + 500 = 666.
It is a super-2 number, since 2×314711235002 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (31471123501) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3492292 + ... + 3501291.
Almost surely, 231471123500 is an apocalyptic number.
31471123500 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
31471123500 is an abundant number, since it is smaller than the sum of its proper divisors (67809794964).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31471123500 is a wasteful number, since it uses less digits than its factorization.
31471123500 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6993608 (or 6993593 counting only the distinct ones).
The product of its (nonzero) digits is 2520, while the sum is 27.
The spelling of 31471123500 in words is "thirty-one billion, four hundred seventy-one million, one hundred twenty-three thousand, five hundred".
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