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3148428248513 is a prime number
BaseRepresentation
bin101101110100001100111…
…100101000010111000001
3102010222122101012112121122
4231310030330220113001
5403040440112423023
610410211252002025
7443315662360352
oct55641474502701
912128571175548
103148428248513
111004271737759
1242a22a300315
1319ab845872a2
14ac555a27d29
1556d703542c8
hex2dd0cf285c1

3148428248513 has 2 divisors, whose sum is σ = 3148428248514. Its totient is φ = 3148428248512.

The previous prime is 3148428248477. The next prime is 3148428248533. The reversal of 3148428248513 is 3158428248413.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2184551988529 + 963876259984 = 1478023^2 + 981772^2 .

It is a cyclic number.

It is not a de Polignac number, because 3148428248513 - 220 = 3148427199937 is a prime.

It is a super-3 number, since 3×31484282485133 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (3148428248533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1574214124256 + 1574214124257.

It is an arithmetic number, because the mean of its divisors is an integer number (1574214124257).

Almost surely, 23148428248513 is an apocalyptic number.

It is an amenable number.

3148428248513 is a deficient number, since it is larger than the sum of its proper divisors (1).

3148428248513 is an equidigital number, since it uses as much as digits as its factorization.

3148428248513 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5898240, while the sum is 53.

The spelling of 3148428248513 in words is "three trillion, one hundred forty-eight billion, four hundred twenty-eight million, two hundred forty-eight thousand, five hundred thirteen".