Base | Representation |
---|---|
bin | 11101010100101011… |
… | …101100100000010111 |
3 | 10000021021112201100002 |
4 | 131110223230200113 |
5 | 1003440242333303 |
6 | 22244135441515 |
7 | 2163145301522 |
oct | 352453544027 |
9 | 100237481302 |
10 | 31485511703 |
11 | 12397828a58 |
12 | 612852629b |
13 | 2c7a0838c9 |
14 | 1749859bb9 |
15 | c44260788 |
hex | 754aec817 |
31485511703 has 2 divisors, whose sum is σ = 31485511704. Its totient is φ = 31485511702.
The previous prime is 31485511663. The next prime is 31485511709. The reversal of 31485511703 is 30711558413.
It is a strong prime.
It is an emirp because it is prime and its reverse (30711558413) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31485511703 - 212 = 31485507607 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31485511709) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15742755851 + 15742755852.
It is an arithmetic number, because the mean of its divisors is an integer number (15742755852).
Almost surely, 231485511703 is an apocalyptic number.
31485511703 is a deficient number, since it is larger than the sum of its proper divisors (1).
31485511703 is an equidigital number, since it uses as much as digits as its factorization.
31485511703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 38.
The spelling of 31485511703 in words is "thirty-one billion, four hundred eighty-five million, five hundred eleven thousand, seven hundred three".
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