Base | Representation |
---|---|
bin | 1001001010101011000… |
… | …01010101110011110011 |
3 | 1010002222121202112122202 |
4 | 10211111201111303303 |
5 | 20130023124303201 |
6 | 400405524453415 |
7 | 31520120602001 |
oct | 4452541256363 |
9 | 1102877675582 |
10 | 314967416051 |
11 | 111638993532 |
12 | 51061b4a26b |
13 | 239169a9802 |
14 | 1135ccc3a71 |
15 | 82d66d8c6b |
hex | 4955855cf3 |
314967416051 has 2 divisors, whose sum is σ = 314967416052. Its totient is φ = 314967416050.
The previous prime is 314967416021. The next prime is 314967416053. The reversal of 314967416051 is 150614769413.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 314967416051 - 234 = 297787546867 is a prime.
Together with 314967416053, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 314967415987 and 314967416005.
It is not a weakly prime, because it can be changed into another prime (314967416053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157483708025 + 157483708026.
It is an arithmetic number, because the mean of its divisors is an integer number (157483708026).
Almost surely, 2314967416051 is an apocalyptic number.
314967416051 is a deficient number, since it is larger than the sum of its proper divisors (1).
314967416051 is an equidigital number, since it uses as much as digits as its factorization.
314967416051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 544320, while the sum is 47.
The spelling of 314967416051 in words is "three hundred fourteen billion, nine hundred sixty-seven million, four hundred sixteen thousand, fifty-one".
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