Base | Representation |
---|---|
bin | 11101010101100100… |
… | …110101111110010001 |
3 | 10000022022201211101102 |
4 | 131111210311332101 |
5 | 1004003111231224 |
6 | 22245432514145 |
7 | 2163416525051 |
oct | 352544657621 |
9 | 100268654342 |
10 | 31500492689 |
11 | 123a5230436 |
12 | 613154b955 |
13 | 2c801ca6b3 |
14 | 174b839561 |
15 | c4571e4ae |
hex | 755935f91 |
31500492689 has 2 divisors, whose sum is σ = 31500492690. Its totient is φ = 31500492688.
The previous prime is 31500492629. The next prime is 31500492691. The reversal of 31500492689 is 98629400513.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28145766289 + 3354726400 = 167767^2 + 57920^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31500492689 is a prime.
Together with 31500492691, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (31500492629) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15750246344 + 15750246345.
It is an arithmetic number, because the mean of its divisors is an integer number (15750246345).
Almost surely, 231500492689 is an apocalyptic number.
It is an amenable number.
31500492689 is a deficient number, since it is larger than the sum of its proper divisors (1).
31500492689 is an equidigital number, since it uses as much as digits as its factorization.
31500492689 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 466560, while the sum is 47.
The spelling of 31500492689 in words is "thirty-one billion, five hundred million, four hundred ninety-two thousand, six hundred eighty-nine".
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