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31503042554012 = 22171776126084119
BaseRepresentation
bin1110010100110110111111…
…01010010010100010011100
311010112122212012102122200022
413022123133222102202130
513112121212343212022
6151000144205251312
76431006522323511
oct712333752224234
9133478765378608
1031503042554012
11a04640226a297
123649601263b38
131476954cb9273
147aca80b39308
153996ee320c42
hex1ca6dfa9289c

31503042554012 has 24 divisors (see below), whose sum is σ = 58376573569440. Its totient is φ = 14824125941760.

The previous prime is 31503042553999. The next prime is 31503042554021. The reversal of 31503042554012 is 21045524030513.

It is a super-3 number, since 3×315030425540123 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11834312 + ... + 14249807.

It is an arithmetic number, because the mean of its divisors is an integer number (2432357232060).

Almost surely, 231503042554012 is an apocalyptic number.

It is an amenable number.

31503042554012 is a deficient number, since it is larger than the sum of its proper divisors (26873531015428).

31503042554012 is a wasteful number, since it uses less digits than its factorization.

31503042554012 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26101901 (or 26101899 counting only the distinct ones).

The product of its (nonzero) digits is 72000, while the sum is 35.

Adding to 31503042554012 its reverse (21045524030513), we get a palindrome (52548566584525).

The spelling of 31503042554012 in words is "thirty-one trillion, five hundred three billion, forty-two million, five hundred fifty-four thousand, twelve".

Divisors: 1 2 4 17 34 68 17761 35522 71044 301937 603874 1207748 26084119 52168238 104336476 443430023 886860046 1773720092 463280037559 926560075118 1853120150236 7875760638503 15751521277006 31503042554012