Base | Representation |
---|---|
bin | 101101110110110100101… |
… | …111111110001101011111 |
3 | 102011020220120121020222021 |
4 | 231312310233332031133 |
5 | 403112221314034211 |
6 | 10411354500401011 |
7 | 443445515546623 |
oct | 55666457761537 |
9 | 12136816536867 |
10 | 3151243502431 |
11 | 1005486893692 |
12 | 42a8950a6167 |
13 | 19b2128c55cb |
14 | ac74189d183 |
15 | 56e875a3771 |
hex | 2ddb4bfe35f |
3151243502431 has 2 divisors, whose sum is σ = 3151243502432. Its totient is φ = 3151243502430.
The previous prime is 3151243502387. The next prime is 3151243502443. The reversal of 3151243502431 is 1342053421513.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3151243502431 is a prime.
It is a super-3 number, since 3×31512435024313 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3151243502831) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1575621751215 + 1575621751216.
It is an arithmetic number, because the mean of its divisors is an integer number (1575621751216).
Almost surely, 23151243502431 is an apocalyptic number.
3151243502431 is a deficient number, since it is larger than the sum of its proper divisors (1).
3151243502431 is an equidigital number, since it uses as much as digits as its factorization.
3151243502431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 3151243502431 its reverse (1342053421513), we get a palindrome (4493296923944).
The spelling of 3151243502431 in words is "three trillion, one hundred fifty-one billion, two hundred forty-three million, five hundred two thousand, four hundred thirty-one".
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