Base | Representation |
---|---|
bin | 100011110100110101100111… |
… | …0010110001000100000110010 |
3 | 1112022202200020212112202012102 |
4 | 1013221223032112020200302 |
5 | 312301002413334303200 |
6 | 3034114305110300402 |
7 | 123243021346645301 |
oct | 10751531626104062 |
9 | 1468680225482172 |
10 | 315125212416050 |
11 | 91454941125483 |
12 | 2b415464057702 |
13 | 106ab245680cba |
14 | 57b61daa0a438 |
15 | 26671e388d6d5 |
hex | 11e9ace588832 |
315125212416050 has 48 divisors (see below), whose sum is σ = 587387191007880. Its totient is φ = 125780602967040.
The previous prime is 315125212416037. The next prime is 315125212416061. The reversal of 315125212416050 is 50614212521513.
It can be written as a sum of positive squares in 12 ways, for example, as 51998564266009 + 263126648150041 = 7211003^2 + 16221179^2 .
It is a junction number, because it is equal to n+sod(n) for n = 315125212415995 and 315125212416013.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 45435674 + ... + 51910026.
Almost surely, 2315125212416050 is an apocalyptic number.
315125212416050 is a deficient number, since it is larger than the sum of its proper divisors (272261978591830).
315125212416050 is a wasteful number, since it uses less digits than its factorization.
315125212416050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6476447 (or 6476442 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 38.
Adding to 315125212416050 its reverse (50614212521513), we get a palindrome (365739424937563).
The spelling of 315125212416050 in words is "three hundred fifteen trillion, one hundred twenty-five billion, two hundred twelve million, four hundred sixteen thousand, fifty".
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