Base | Representation |
---|---|
bin | 1001001010111110011… |
… | …11001011000000000000 |
3 | 1010010101222111021100222 |
4 | 10211133033023000000 |
5 | 20130341342102334 |
6 | 400434030402212 |
7 | 31524140263520 |
oct | 4453717130000 |
9 | 1103358437328 |
10 | 315130425344 |
11 | 111711a00859 |
12 | 510a8660368 |
13 | 239416b1c07 |
14 | 113767d7680 |
15 | 82e5b87d2e |
hex | 495f3cb000 |
315130425344 has 104 divisors (see below), whose sum is σ = 728308334880. Its totient is φ = 133537333248.
The previous prime is 315130425341. The next prime is 315130425347. The reversal of 315130425344 is 443524031513.
It is an interprime number because it is at equal distance from previous prime (315130425341) and next prime (315130425347).
It is not an unprimeable number, because it can be changed into a prime (315130425341) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2490062 + ... + 2613554.
Almost surely, 2315130425344 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 315130425344, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (364154167440).
315130425344 is an abundant number, since it is smaller than the sum of its proper divisors (413177909536).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
315130425344 is an equidigital number, since it uses as much as digits as its factorization.
315130425344 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 123613 (or 123591 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 315130425344 its reverse (443524031513), we get a palindrome (758654456857).
The spelling of 315130425344 in words is "three hundred fifteen billion, one hundred thirty million, four hundred twenty-five thousand, three hundred forty-four".
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