Base | Representation |
---|---|
bin | 101101110111100010000… |
… | …101100000001001101111 |
3 | 102011022212120211200202202 |
4 | 231313202011200021233 |
5 | 403120301023334244 |
6 | 10412002151212115 |
7 | 443503412653223 |
oct | 55674205401157 |
9 | 12138776750682 |
10 | 3152004121199 |
11 | 100583717683a |
12 | 42aa6797703b |
13 | 19b30436a49b |
14 | ac7b48d6783 |
15 | 56ece24c04e |
hex | 2dde216026f |
3152004121199 has 2 divisors, whose sum is σ = 3152004121200. Its totient is φ = 3152004121198.
The previous prime is 3152004121183. The next prime is 3152004121219. The reversal of 3152004121199 is 9911214002513.
3152004121199 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3152004121199 - 24 = 3152004121183 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3152004121169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1576002060599 + 1576002060600.
It is an arithmetic number, because the mean of its divisors is an integer number (1576002060600).
Almost surely, 23152004121199 is an apocalyptic number.
3152004121199 is a deficient number, since it is larger than the sum of its proper divisors (1).
3152004121199 is an equidigital number, since it uses as much as digits as its factorization.
3152004121199 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19440, while the sum is 38.
The spelling of 3152004121199 in words is "three trillion, one hundred fifty-two billion, four million, one hundred twenty-one thousand, one hundred ninety-nine".
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