Base | Representation |
---|---|
bin | 1001001011001001010… |
… | …00101100010000100101 |
3 | 1010010122021221000011021 |
4 | 10211210220230100211 |
5 | 20131033034020003 |
6 | 400451024011141 |
7 | 31526320205314 |
oct | 4454450542045 |
9 | 1103567830137 |
10 | 315221001253 |
11 | 111759045884 |
12 | 51112a60ab1 |
13 | 239573a6022 |
14 | 1138485427b |
15 | 82edaca2bd |
hex | 4964a2c425 |
315221001253 has 2 divisors, whose sum is σ = 315221001254. Its totient is φ = 315221001252.
The previous prime is 315221001241. The next prime is 315221001257. The reversal of 315221001253 is 352100122513.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 261997588449 + 53223412804 = 511857^2 + 230702^2 .
It is a cyclic number.
It is not a de Polignac number, because 315221001253 - 221 = 315218904101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (315221001257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157610500626 + 157610500627.
It is an arithmetic number, because the mean of its divisors is an integer number (157610500627).
Almost surely, 2315221001253 is an apocalyptic number.
It is an amenable number.
315221001253 is a deficient number, since it is larger than the sum of its proper divisors (1).
315221001253 is an equidigital number, since it uses as much as digits as its factorization.
315221001253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 315221001253 its reverse (352100122513), we get a palindrome (667321123766).
The spelling of 315221001253 in words is "three hundred fifteen billion, two hundred twenty-one million, one thousand, two hundred fifty-three".
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