Base | Representation |
---|---|
bin | 1001001011001010100… |
… | …11001001100000000101 |
3 | 1010010200001212110101222 |
4 | 10211211103021200011 |
5 | 20131043411143302 |
6 | 400452102330125 |
7 | 31526513621633 |
oct | 4454523114005 |
9 | 1103601773358 |
10 | 315232131077 |
11 | 111764357886 |
12 | 51116729945 |
13 | 239597a1c16 |
14 | 11386110353 |
15 | 82eea77da2 |
hex | 49654c9805 |
315232131077 has 2 divisors, whose sum is σ = 315232131078. Its totient is φ = 315232131076.
The previous prime is 315232131047. The next prime is 315232131079. The reversal of 315232131077 is 770131232513.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 243338970436 + 71893160641 = 493294^2 + 268129^2 .
It is a cyclic number.
It is not a de Polignac number, because 315232131077 - 28 = 315232130821 is a prime.
Together with 315232131079, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (315232131079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157616065538 + 157616065539.
It is an arithmetic number, because the mean of its divisors is an integer number (157616065539).
Almost surely, 2315232131077 is an apocalyptic number.
It is an amenable number.
315232131077 is a deficient number, since it is larger than the sum of its proper divisors (1).
315232131077 is an equidigital number, since it uses as much as digits as its factorization.
315232131077 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26460, while the sum is 35.
The spelling of 315232131077 in words is "three hundred fifteen billion, two hundred thirty-two million, one hundred thirty-one thousand, seventy-seven".
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