Base | Representation |
---|---|
bin | 11101010111111011… |
… | …110000010001110111 |
3 | 10000102002011201002020 |
4 | 131113323300101313 |
5 | 1004043223144421 |
6 | 22253404444223 |
7 | 2164410012420 |
oct | 352773602167 |
9 | 100362151066 |
10 | 31540053111 |
11 | 124155a07a6 |
12 | 6142849673 |
13 | 2c8846c128 |
14 | 1752bb6647 |
15 | c48e35dc6 |
hex | 757ef0477 |
31540053111 has 32 divisors (see below), whose sum is σ = 50972832768. Its totient is φ = 16956656640.
The previous prime is 31540053047. The next prime is 31540053113. The reversal of 31540053111 is 11135004513.
It is not a de Polignac number, because 31540053111 - 26 = 31540053047 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31540053113) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 505786 + ... + 564711.
It is an arithmetic number, because the mean of its divisors is an integer number (1592901024).
Almost surely, 231540053111 is an apocalyptic number.
31540053111 is a deficient number, since it is larger than the sum of its proper divisors (19432779657).
31540053111 is a wasteful number, since it uses less digits than its factorization.
31540053111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1070591.
The product of its (nonzero) digits is 900, while the sum is 24.
Adding to 31540053111 its reverse (11135004513), we get a palindrome (42675057624).
It can be divided in two parts, 315400 and 53111, that added together give a triangular number (368511 = T858).
The spelling of 31540053111 in words is "thirty-one billion, five hundred forty million, fifty-three thousand, one hundred eleven".
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