Base | Representation |
---|---|
bin | 101101111001011010011… |
… | …100001110000000010111 |
3 | 102011112002022100202010011 |
4 | 231321122130032000113 |
5 | 403133414433421403 |
6 | 10412534402141051 |
7 | 443604432030514 |
oct | 55713234160027 |
9 | 12145068322104 |
10 | 3154023342103 |
11 | 1006682a51347 |
12 | 42b330051787 |
13 | 19b5667b445a |
14 | ac926b5630b |
15 | 5709b659a6d |
hex | 2de5a70e017 |
3154023342103 has 2 divisors, whose sum is σ = 3154023342104. Its totient is φ = 3154023342102.
The previous prime is 3154023342097. The next prime is 3154023342121. The reversal of 3154023342103 is 3012433204513.
It is a happy number.
3154023342103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3154023342103 - 221 = 3154021244951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3154023342143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1577011671051 + 1577011671052.
It is an arithmetic number, because the mean of its divisors is an integer number (1577011671052).
Almost surely, 23154023342103 is an apocalyptic number.
3154023342103 is a deficient number, since it is larger than the sum of its proper divisors (1).
3154023342103 is an equidigital number, since it uses as much as digits as its factorization.
3154023342103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 3154023342103 its reverse (3012433204513), we get a palindrome (6166456546616).
The spelling of 3154023342103 in words is "three trillion, one hundred fifty-four billion, twenty-three million, three hundred forty-two thousand, one hundred three".
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