Base | Representation |
---|---|
bin | 100011110111001101000111… |
… | …0010101111011001010000111 |
3 | 1112100220210000122011001011202 |
4 | 1013232122032111323022013 |
5 | 312321320214332242043 |
6 | 3034523552423253115 |
7 | 123305356564633352 |
oct | 10756321625731207 |
9 | 1470823018131152 |
10 | 315450556134023 |
11 | 9156a914182142 |
12 | 2b468520baa19b |
13 | 10702b23cacb1b |
14 | 57c7c61a09299 |
15 | 26708d5eb71b8 |
hex | 11ee68e57b287 |
315450556134023 has 2 divisors, whose sum is σ = 315450556134024. Its totient is φ = 315450556134022.
The previous prime is 315450556134017. The next prime is 315450556134031. The reversal of 315450556134023 is 320431655054513.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 315450556134023 - 214 = 315450556117639 is a prime.
It is a super-4 number, since 4×3154505561340234 (a number of 59 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (315450552134023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157725278067011 + 157725278067012.
It is an arithmetic number, because the mean of its divisors is an integer number (157725278067012).
Almost surely, 2315450556134023 is an apocalyptic number.
315450556134023 is a deficient number, since it is larger than the sum of its proper divisors (1).
315450556134023 is an equidigital number, since it uses as much as digits as its factorization.
315450556134023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3240000, while the sum is 47.
The spelling of 315450556134023 in words is "three hundred fifteen trillion, four hundred fifty billion, five hundred fifty-six million, one hundred thirty-four thousand, twenty-three".
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