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31550143981 is a prime number
BaseRepresentation
bin11101011000100010…
…001111110111101101
310000102210011101011011
4131120202033313231
51004103314101411
622254405025221
72164561541026
oct353042176755
9100383141134
1031550143981
1112420263164
1261460b5211
132c8a593165
141754281c4d
15c49c7ac21
hex75888fded

31550143981 has 2 divisors, whose sum is σ = 31550143982. Its totient is φ = 31550143980.

The previous prime is 31550143979. The next prime is 31550144027. The reversal of 31550143981 is 18934105513.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 30712562500 + 837581481 = 175250^2 + 28941^2 .

It is a cyclic number.

It is not a de Polignac number, because 31550143981 - 21 = 31550143979 is a prime.

It is a super-2 number, since 2×315501439812 (a number of 22 digits) contains 22 as substring.

Together with 31550143979, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31550143921) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15775071990 + 15775071991.

It is an arithmetic number, because the mean of its divisors is an integer number (15775071991).

Almost surely, 231550143981 is an apocalyptic number.

It is an amenable number.

31550143981 is a deficient number, since it is larger than the sum of its proper divisors (1).

31550143981 is an equidigital number, since it uses as much as digits as its factorization.

31550143981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64800, while the sum is 40.

The spelling of 31550143981 in words is "thirty-one billion, five hundred fifty million, one hundred forty-three thousand, nine hundred eighty-one".