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31550441322011 is a prime number
BaseRepresentation
bin1110010110001111010001…
…10110001111011000011011
311010201012012111120112211012
413023013220312033120123
513113410300434301021
6151034023405324135
76434305230234503
oct713075066173033
9133635174515735
1031550441322011
11a064515676227
12365682ab6664b
13147b269b74351
147b1099bc6a03
1539aa7564035b
hex1cb1e8d8f61b

31550441322011 has 2 divisors, whose sum is σ = 31550441322012. Its totient is φ = 31550441322010.

The previous prime is 31550441321989. The next prime is 31550441322013. The reversal of 31550441322011 is 11022314405513.

It is a strong prime.

It is an emirp because it is prime and its reverse (11022314405513) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31550441322011 is a prime.

It is a super-2 number, since 2×315504413220112 (a number of 28 digits) contains 22 as substring.

Together with 31550441322013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (31550441322013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15775220661005 + 15775220661006.

It is an arithmetic number, because the mean of its divisors is an integer number (15775220661006).

Almost surely, 231550441322011 is an apocalyptic number.

31550441322011 is a deficient number, since it is larger than the sum of its proper divisors (1).

31550441322011 is an equidigital number, since it uses as much as digits as its factorization.

31550441322011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 31550441322011 its reverse (11022314405513), we get a palindrome (42572755727524).

The spelling of 31550441322011 in words is "thirty-one trillion, five hundred fifty billion, four hundred forty-one million, three hundred twenty-two thousand, eleven".