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3161141491200 = 293527112324347
BaseRepresentation
bin101110000000000010101…
…101110011011000000000
3102012012110101102011222220
4232000002231303120000
5403243004210204300
610420113000531040
7444246014222010
oct56000255633000
912165411364886
103161141491200
1110096a5a630a0
12430797a80a80
1319c12c4169b4
14ad000269c40
1557366510da0
hex2e002b73600

3161141491200 has 2880 divisors, whose sum is σ = 14222881677312. Its totient is φ = 600632524800.

The previous prime is 3161141491111. The next prime is 3161141491219. The reversal of 3161141491200 is 21941411613.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (33).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 67258329577 + ... + 67258329623.

Almost surely, 23161141491200 is an apocalyptic number.

3161141491200 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3161141491200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (7111440838656).

3161141491200 is an abundant number, since it is smaller than the sum of its proper divisors (11061740186112).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3161141491200 is a wasteful number, since it uses less digits than its factorization.

3161141491200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 185 (or 141 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 33.

The spelling of 3161141491200 in words is "three trillion, one hundred sixty-one billion, one hundred forty-one million, four hundred ninety-one thousand, two hundred".