Base | Representation |
---|---|
bin | 1001001101000000100… |
… | …01001100100000100011 |
3 | 1010020020000111022220222 |
4 | 10212200101030200203 |
5 | 20140110144143401 |
6 | 401134203353255 |
7 | 31563156121052 |
oct | 4464021144043 |
9 | 1106200438828 |
10 | 316221474851 |
11 | 112121862467 |
12 | 51351b2282b |
13 | 23a8674a939 |
14 | 1143b686399 |
15 | 835b851c1b |
hex | 49a044c823 |
316221474851 has 2 divisors, whose sum is σ = 316221474852. Its totient is φ = 316221474850.
The previous prime is 316221474817. The next prime is 316221474853. The reversal of 316221474851 is 158474122613.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-316221474851 is a prime.
Together with 316221474853, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (316221474853) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158110737425 + 158110737426.
It is an arithmetic number, because the mean of its divisors is an integer number (158110737426).
Almost surely, 2316221474851 is an apocalyptic number.
316221474851 is a deficient number, since it is larger than the sum of its proper divisors (1).
316221474851 is an equidigital number, since it uses as much as digits as its factorization.
316221474851 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 322560, while the sum is 44.
The spelling of 316221474851 in words is "three hundred sixteen billion, two hundred twenty-one million, four hundred seventy-four thousand, eight hundred fifty-one".
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