Base | Representation |
---|---|
bin | 1001001101000001011… |
… | …11101101101000100010 |
3 | 1010020020120112202212020 |
4 | 10212200233231220202 |
5 | 20140114221143400 |
6 | 401135051042310 |
7 | 31563314120502 |
oct | 4464057555042 |
9 | 1106216482766 |
10 | 316229474850 |
11 | 112126326a33 |
12 | 51354740396 |
13 | 23a882bc073 |
14 | 1143c769a02 |
15 | 835c3d22a0 |
hex | 49a0beda22 |
316229474850 has 48 divisors (see below), whose sum is σ = 811292181120. Its totient is φ = 81420001600.
The previous prime is 316229474833. The next prime is 316229474851. The reversal of 316229474850 is 58474922613.
It is a junction number, because it is equal to n+sod(n) for n = 316229474793 and 316229474802.
It is not an unprimeable number, because it can be changed into a prime (316229474851) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 36343866 + ... + 36352565.
It is an arithmetic number, because the mean of its divisors is an integer number (16901920440).
It is a 1-persistent number, because it is pandigital, but 2⋅316229474850 = 632458949700 is not.
Almost surely, 2316229474850 is an apocalyptic number.
316229474850 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
316229474850 is an abundant number, since it is smaller than the sum of its proper divisors (495062706270).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
316229474850 is a wasteful number, since it uses less digits than its factorization.
316229474850 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72696475 (or 72696470 counting only the distinct ones).
The product of its (nonzero) digits is 2903040, while the sum is 51.
The spelling of 316229474850 in words is "three hundred sixteen billion, two hundred twenty-nine million, four hundred seventy-four thousand, eight hundred fifty".
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