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316251134341231 is a prime number
BaseRepresentation
bin100011111101000001111010…
…0100001011011000001101111
31112110202022110022021202100011
41013322003310201123001233
5312422424310342404411
63040335433200514051
7123420250632260605
oct10772036441330157
91473668408252304
10316251134341231
119184939775a531
122b57770901b927
131076047a99492b
1458148caa83875
15268663ee1ec21
hex11fa0f485b06f

316251134341231 has 2 divisors, whose sum is σ = 316251134341232. Its totient is φ = 316251134341230.

The previous prime is 316251134341183. The next prime is 316251134341279. The reversal of 316251134341231 is 132143431152613.

It is a balanced prime because it is at equal distance from previous prime (316251134341183) and next prime (316251134341279).

It is a cyclic number.

It is not a de Polignac number, because 316251134341231 - 217 = 316251134210159 is a prime.

It is a super-2 number, since 2×3162511343412312 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (316251134347231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158125567170615 + 158125567170616.

It is an arithmetic number, because the mean of its divisors is an integer number (158125567170616).

Almost surely, 2316251134341231 is an apocalyptic number.

316251134341231 is a deficient number, since it is larger than the sum of its proper divisors (1).

316251134341231 is an equidigital number, since it uses as much as digits as its factorization.

316251134341231 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 155520, while the sum is 40.

Adding to 316251134341231 its reverse (132143431152613), we get a palindrome (448394565493844).

The spelling of 316251134341231 in words is "three hundred sixteen trillion, two hundred fifty-one billion, one hundred thirty-four million, three hundred forty-one thousand, two hundred thirty-one".