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316356146020933 is a prime number
BaseRepresentation
bin100011111101110010110011…
…1101101001100001001000101
31112111010100111202021210200121
41013323211213231030021011
5312431134341340132213
63040500001313341541
7123430656132650314
oct10773454755141105
91474110452253617
10316356146020933
119188998504a787
122b593b352678b1
131076a344892205
145819a0d56627b
15268923911b88d
hex11fb967b4c245

316356146020933 has 2 divisors, whose sum is σ = 316356146020934. Its totient is φ = 316356146020932.

The previous prime is 316356146020931. The next prime is 316356146020963. The reversal of 316356146020933 is 339020641653613.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 222621857388324 + 93734288632609 = 14920518^2 + 9681647^2 .

It is a cyclic number.

It is not a de Polignac number, because 316356146020933 - 21 = 316356146020931 is a prime.

It is a super-2 number, since 2×3163561460209332 (a number of 30 digits) contains 22 as substring.

Together with 316356146020931, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (316356146020931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158178073010466 + 158178073010467.

It is an arithmetic number, because the mean of its divisors is an integer number (158178073010467).

Almost surely, 2316356146020933 is an apocalyptic number.

It is an amenable number.

316356146020933 is a deficient number, since it is larger than the sum of its proper divisors (1).

316356146020933 is an equidigital number, since it uses as much as digits as its factorization.

316356146020933 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6298560, while the sum is 52.

The spelling of 316356146020933 in words is "three hundred sixteen trillion, three hundred fifty-six billion, one hundred forty-six million, twenty thousand, nine hundred thirty-three".