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316421155553051 is a prime number
BaseRepresentation
bin100011111110010001000101…
…0100100110111111100011011
31112111100120022101012012121102
41013330202022210313330123
5312433221011310144201
63040545512213302015
7123435450131603033
oct10774421244677433
91474316271165542
10316421155553051
119190450525542a
122b5a465893490b
1310773505137893
14581cc1947c8c3
15268ac9155a26b
hex11fc88a937f1b

316421155553051 has 2 divisors, whose sum is σ = 316421155553052. Its totient is φ = 316421155553050.

The previous prime is 316421155553011. The next prime is 316421155553081. The reversal of 316421155553051 is 150355551124613.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 316421155553051 - 210 = 316421155552027 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 316421155552987 and 316421155553005.

It is not a weakly prime, because it can be changed into another prime (316421155553011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158210577776525 + 158210577776526.

It is an arithmetic number, because the mean of its divisors is an integer number (158210577776526).

Almost surely, 2316421155553051 is an apocalyptic number.

316421155553051 is a deficient number, since it is larger than the sum of its proper divisors (1).

316421155553051 is an equidigital number, since it uses as much as digits as its factorization.

316421155553051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1350000, while the sum is 47.

The spelling of 316421155553051 in words is "three hundred sixteen trillion, four hundred twenty-one billion, one hundred fifty-five million, five hundred fifty-three thousand, fifty-one".